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144x-16x^2=224
We move all terms to the left:
144x-16x^2-(224)=0
a = -16; b = 144; c = -224;
Δ = b2-4ac
Δ = 1442-4·(-16)·(-224)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6400}=80$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(144)-80}{2*-16}=\frac{-224}{-32} =+7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(144)+80}{2*-16}=\frac{-64}{-32} =+2 $
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